Irregular six-sided figure with labeled lengths for some of the sides. reading clockwise, side lengths and orientations are 26 millimeters angled diagonally down, 26 millimeters angled diagonally up, unlabeled vertical, unlabeled angled diagonally down, unlabeled angled diagonally up, and unlabeled vertical. there is a vertical dashed line between the angled diagonal lines and the three vertical lines are parallel. there is a dashed line connecting the two angled diagonally lines on the left labeled 14 millimeters and connects to the 26 millimeters line at a right angle. there is a dashed line connecting the two angled diagonally lines on the right labeled 14 millimeters and connects to the 26 millimeters line at a right angle. what is the area of the figure? 132 mm² 364 mm² 728 mm² 9464 mm²

I've been working on this for a few days and i just don't understand, it's due in a few hours. you.the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α.part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part bsuppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i.e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case.part cnow try a numerical problem. what is the direction of the vector w = < -1, 6 > ?