What are the vertex and axis of symmetry of the parabola y=3x^2-24x+38?

see explanation

Step-by-step explanation:

given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex which is also the axis of symmetry is

= -

y = 3x² - 24x + 38 is in standard form

with a = 3, b = - 24 and c = 38, hence

= - = 4

Substitute x = 4 into the equation for corresponding y- coordinate

y = 3(4)² - 24(4) + 38 = 48 - 96 + 38 = - 10

vertex = (4, - 10)

equation of axis of symmetry is x = 4

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40