Find the equation of the line using the point-slope forumla. write the final equation using the slope-intercept form. parallel to y = 3 x − 2 and passes through the point ( − 3 , − 14 )

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = 3x - 2 is in this form with slope m = 3

• Parallel lines have equal slopes

Hence the slope of the parallel line = 3

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 3 and (a, b) = (- 3, - 14), hence

y + 14 = 3(x + 3) ← in point- slope form

Distribute and simplify

y + 14 = 3x + 9 ( subtract 14 from both sides )

y = 3x - 5 ← in slope- intercept form

b i think

step-by-step explanation:

not really sure