Find the area of each parallelogram. what is the relationship between the areas?

Area of parallelogram is given by:

where b is the base and h is the height of parallelogram.

In parallelogram TQRS.

Coordinate of TQRS are;

T(8, 16), Q(4, 4), R(16, 4) and S(20, 16)

Coordinate of T'Q'R'S' are;

T'(2, 4), Q'(1, 1), R'(4, 1) and S'(5, 4)

Find the length of QR and PT:

Using distance(D) formula:

units

Similarly;

For PT:

From the graph:

P(8, 4) and T(8, 16), then

units

In parallelogram TQRS

PT represents the height and QR represents the base of the parallelogram respectively.

then;

Area of parallelogram TQRS =

⇒Area of parallelogram TQRS = unit square.

Now, in parallelogram T'Q'R'S'

Q'R' represents the base and P'T' represents the height of the parallelogram respectively.

here, P'(2, 1)

Find the length of Q'R' and P'T':

units

units

Then;

Area of parallelogram T'Q'R'S' =

Area of parallelogram T'Q'R'S' = unit square.

Now, we have to find the relationship between the areas.

then;

the relationship between the areas of TQRS and T'Q'R'S' is:

d. all of the above

step-by-step explanation:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.