When the outliers are removed, how does the mean change? dot plot with 1 on 18, 2 on 38, 1 on 40, 3 on 44, 1 on 46, 1 on 48 the mean decreases by 2.75. the mean increases by 2.75. the mean increases by 3.25. there are no outliers.

Step-by-step explanation:

Let us calculat the average medians first

Average (mean): μ=39

Minimum: 18

Maximum: 48

Variance: 99.6666666667

Standard deviation σ=9.98331942125

Corrected sample standard deviation s=10.9361784916

Coefficient of variation cV=0.280414833118

Signal-to-noise ratio SNR=3.5661451603

Median: 42

Outlier -18

When we remove 18, the average becomes

Mean =43.2

Setwise:

Mean of dot plot 1=32

When outlier removed mean =39

B

Step-by-step explanation: Took the test

answer: i'm not sure

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?