There are 10 vehicles in a parking lot: 3 suvs and 7 trucks. the probability that any 7 randomly chosen parking spots have 2 suvs and 5 trucks or 3 suvs and 4 trucks . the probability that of any 7 randomly chosen vehicles, exactly 1 is an suv .

The probability that any 7 randomly chosen parking spots have 2 SUVs and 5 trucks or 3 SUVs and 4 trucks is 49/60

The probability that of any 7 randomly chosen vehicles, exactly 1 is an SUV is = 7/40

Step-by-step explanation:

probability of taking 7 vehicles from 10 vehicles = 10C₇

number of ways taking 2 SUVs and 5 trucks  = 3C₂* 7C₅ = 63

number of ways taking 3 SUVs and 4 trucks =3C₁*7C₄ = 35

number of ways taking  2 SUVs and 5 trucks or 3 SUVs and 4 trucks = 63 + 35 = 98

The probability that any 7 randomly chosen parking spots have 2 SUVs and 5 trucks or 3 SUVs and 4 trucks is = 98/120 = 49/60

number of ways taking 7 randomly chosen vehicles, exactly 1 is an SUV = 3C₁*7C₆ = 21

The probability that of any 7 randomly chosen vehicles, exactly 1 is an SUV is 21/120 = 7/40

10 - 75

step-by-step explanation:

there's nothing attached so it's most likely anything in that range.

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).