The volume of a rectangular box is found by multiplying its length, width, and height: v = lwh. a certain box has a volume of b3 + 3b2 - 4b - 12. factor the four-term polynomial to find the dimensions of the box. hint: use factoring by grouping to factor the four term polynomial first.

  length, width, and height are (b+2), (b-2), (b+3)

Step-by-step explanation:

Doing what the problem statement tells you to do, you get ...

  (b^3 +3b^2) -(4b +12)

  = b^2(b +3) -4(b +3) . . . . . factor each pair of terms

  = (b^2 -4)(b +3) . . . . . . . . . write as a product

  = (b -2)(b +2)(b +3) . . . . . . use the factoring of the difference of squares

The three factors are (b-2), (b+2), and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.

true

step-by-step explanation: