Identify an equation in point-slope form for the line perpendicular to y = -1/3x - 6 that passes through (-1, 5). a. y + 1 = 3(x - 5) b. y + 5 = 1/3(x - 1) c. y - 5 = -1/3(x + 1) d. y - 5 =3(x + 1)

Correct choice is D

Step-by-step explanation:

The slope of the line is

Perpendicular lines slopes satisfy the condtion:

then the slope of the perpendicular line is

The equation in point-slope form of the line that passes through the point (-1, 5) is

whats the

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen