Find the answer
29°
36°
49°
61°

Central angle CBA is a right angle, so it is 90 degrees. This means the arc measure from A to C, following the shortest path on the curve, is 90 degrees. This is minor arc CA. A minor arc is one that is less than 180 degrees in measure.

We want to find the measure of minor arc DE. This is the last piece of the puzzle, so to speak, that forms the entire arc ACD. This arc is 180 degrees because AD is a diameter.

So,

(minor arc DE) + (minor arc EC) + (minor arc CA) = arc ACD

x + 61 + 90 = 180

x + 151 = 180

x + 151 - 151 = 180 - 151 .... subtract 151 from both sides

x = 29

Minor arc DE is 29 degrees.

Check out the attached image below if you're still stuck. Hopefully the image clears any confusion you may have.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v