Find the slope-intercept form of the equation of the line that passes through the point (5,1) and is perpendicular to the line 2x + 5y = 10

The slope-intercept form:

m - slope

b - y-intercept

Convert 2x + 5y = 10 to the slope0intercept form:

       subtract 2x from both sides

      divide both sides by 5

Let and

We have

Therefore

We have the equation of a line:

Put the coordinates of the point (5, 1) to the equation of a line:

      subtract from both sides

what are you trying to solve here

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb