Q=12nv2 the dynamic pressure q generated by a fluid moving with velocity v can be found using the formula above, where n is the constant density of the fluid. an aeronautical engineer users the formula to find the dynamic pressure of a fluid moving with velocity v and the same fluid moving with velocity 1.5v. what is the ratio of the dynamic pressure of the faster fluid to the dynamic pressure of the slower fluid?

Because V is raised to the second power in the original equation the velocity of the slower fluid is V^2.

The faster fluid is 1.5V, which when replaced in the equation becomes 1.5v^2.

The ratio would then be 1.5^2 which equals 2.25

The ratio is 2.25/1

Step-by-step explanation:

Fluid 1

Q = 12 n v^2

Fluid 2

Q =12 n (1.5 v)^2

    =12 n (2.25) v^2

Ratio of the faster fluid to the slower fluid

Fluid 2/Fluid 1

12 n (2.25) v^2

12 n v^2

Canceling 12 and n

(2.25) v^2

v^2

Canceling v^2

2.25

1

The ratio is 2.25/1

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

step-by-step explanation:

your answer is a