Anybody care to me figure this out properly, the lesson did not give me enough infogiven the system of linear equations part a: graph the system of linear equations. part b: use the graph created in part a to determine the solution to the system. part c: algebraically verify the solution from part b.

I, personally, have two favorite ways to solve system of equations.

The first, is substitution. Substitution is where you place a known variable from one equation into the other. In this case, the known variable is y=-5. I will 'substitute' the y=-5 into the y=3x-2

y=3x-2

(-5)=3x-2

-5=3x-2

-3=3x

x=-1

Now we know the x and y value!

(-1,-5)

The second way is much quicker, but isnt always accessible, and that way is graphing. I have attached a graph

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

answer is 8 r5

step-by-step explanation: