QUESTION 2a
We want to find the area of the given right angle triangle.
We use the formula
The height of the triangle is 
.
The base is 
.
We substitute the given values to obtain,
.
This simplifies to get an expression for the area to be
.
QUESTION 2b
The given diagram is a rectangle.
The area of a rectangle is given by the formula
The length of the rectangle is 
and the width of the rectangle is 
.
We substitute the values to obtain the area to be
The expression for the area is
QUESTION 2c.
The given diagram is a rectangle.
The area of a rectangle is given by the formula
The length of the rectangle is 
and the width of the rectangle is 
.
We substitute the values to obtain the area to be
The expression for the area is
QUESTION 2d
The given diagram is a square.
The area of a square is given by,
.
where 
is the length of one side.
The expression for the area is
QUESTION 2e
The given diagram is an isosceles triangle.
The area of this triangle can be found using the formula,
.
The height of the triangle is 
.
The base of the triangle is 
.
The expression for the area is
QUESTION 3a
Perimeter is the distance around the figure.
Let P be the perimeter, then
The expression for the perimeter is
QUESTION 3b
The given figure is a rectangle.
Let P, be the perimeter of the given figure.
This simplifies to
Or
QUESTION 3c
The given figure is a parallelogram.
Perimeter is the distance around the parallelogram
This simplifies to,
Or
QUESTION 3d
The given figure is a rhombus.
The perimeter is the distance around the whole figure.
Let P be the perimeter. Then
This simplifies to,
QUESTION 3e
The given figure is an equilateral triangle.
The perimeter is the distance around this triangle.
Let P be the perimeter, then,
We simplify to get,
QUESTION 3f
The figure is an isosceles triangle so two sides are equal.
We add all the distance around the triangle to find the perimeter.
This implies that,
QUESTION 3g
The given figure is a scalene triangle.
The  perimeter is the distance around the given triangle.
Let P be the perimeter. Then
This simplifies to give us,
QUESTION 3h
The given figure is a trapezium.
The perimeter is the distance around the whole trapezium.
Let P be the perimeter.
Then,
We group like terms to get,
We simplify to get,
mm
QUESTION 3i
The figure is an isosceles triangle.
We add all the distance around the figure to obtain the perimeter.
Let 
be the perimeter.
Then 
We regroup the terms to get,
This will simplify to give us the expression for the perimeter to be
mm.
QUESTION 4a
The given figure is a square.
The area of a square is given by the formula;
where 
is the length of one side of the square.
We substitute this value to obtain;
This simplifies to give the expression of the area to be,
QUESTION 4b
The given figure is a rectangle.
The formula for finding the area of a rectangle is
.
where 
is the length of the rectangle and 
is the width of the rectangle.
We substitute the values into the formula to get,
QUESTION 4c
The given figure is a rectangle.
The formula for finding the area of a rectangle is
.
where 
is the length of the rectangle and 
is the width of the rectangle.
We substitute the values into the formula to get,
The expression for the area is
QUESTION 4d
The given figure is a rectangle.
The formula for finding the area of a rectangle is
.
where 
is the length of the rectangle and 
is the width of the rectangle.
We substitute the values into the formula to get,
The expression for the area is
See attachment for the continuation
