Use the quadrant system to find the area of the polygon. a. 52 square units b. 45 square units c. 36 square units d. 38 square units

For this case, we have that the polygon shown in the figure is composed of four rectangles.

1st rectangle:

It is found in the quadrant formed by the negative axis of the "x" coordinate and the positive axis of the "y" coordinate. This rectangle measures 5 units horizontally and 3 units vertically.

2nd rectangle:

It is found in the quadrant formed by the positive axis of the "x" coordinate and the positive axis of the "y" coordinate. This rectangle measures 4 units horizontally and 2 units vertically.

3rd rectangle:

It is located in the center of the four quadrants. This rectangle measures 5 units horizontally and 2 units vertically.

4th rectangle:

It is in the middle of the quadrant formed by the positive axis of the coordinate "x" and the negative axis of the coordinate "y", and the quadrant formed by the negative axis of the coordinate "x" and the negative axis of the coordinate "Y".

Thus, the total area is given by the sum of the partial areas.

Option B

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet