What are the x and y-intercepts of the line? 2x + 3y = -12 a. x-intercept: -6, y-intercept: 4 b. x-intercept: -6, y-intercept: -4 c. x-intercept: -4, y-intercept: 6 d. x-intercept: 4, y-intercept: -6 everyone!

B

Step-by-step explanation:

To find the y-intercept, plug in x=0 in the original equation. (You want to find what y is when x=0)

2x + 3y = -12

2(0) + 3y = -12 (Plug in x=0)

3y = -12 (2*0=0, so you can ignore that part)

y = -4 (Divide both sides by 3)

This narrows down our choices to either A or B.

To find the x-intercept, plug in y=0 into the original equation. (You want to find what x is when y=0)

2x + 3y = -12

2x + 3(0) = -12 (Plug in y=0)

2x = -12 (3*0=0, so you can ignore that part)

x = -6 (Divide both sides by 2)

If our x intercept is -6 and our y intercept is -4, that makes our answer B.

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.