1. what is the equation of the line that goes through the point and is parallel to the line represented by the equation below? y=-5/6x+3 a. y=-5/6x+4 b. y=-5/6x-6 c. y=-5/6x-4 d. y=-5/6x+6 which equation produces a line that is perpendicular to the line represented by the function below? y=2/5x+9 a. 5x+2y=4 b. 2x-5y=8 c. 5x+2y=-3 d.2x+5y=-7 what is the slope of the line that is parallel to the line represented by the equation below? 4x-5y+-1 a 4/5 b -4/5 c 5/4 d -5/4

1. Missing the point - unanswerable

2. A and C

3. A

Step-by-step explanation:

Recall the slope of a line is parallel if the same slope  and perpendicular if it is the negative reciprocal.

For number 1, each equation has the same slope as the function and will be parallel. Without the point, you cannot determine which one.

For number 2, find an equation that has slope -5/2. Both A and C have this property when converted to slope intercept form.

5x+2y=4                     5x+2y = -3

2y=4-5x                      2y= -3-5x

y=2-5/2 x                    y=-3/2 -5/2 x

For number 3, the slope will be the same as the equation for parallel. Convert the equation 4x-5y=-1 to find the slope.

4x-5y=-1

-5y = -1-4x

y=1/5 + 4/5 x

A is the solution.

dont think so

step-by-step explanation: