Idon’t know how to do this and i need asap

w^9

Step-by-step explanation:

Option 1:

(w^3)^3 can be re-written as (w^3)(w^3)(w^3).  All we have to do now is to add the exponents:  w^(3+3+3) = w^9.

Option 2:  Think of w^3 as (w)(w)(w) and

(w^3)^3 = (w*w*w)*(w*w*w)(w*w*w) = w^9 (after adding up the exponents).

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

f is the midpoint of