Plz can’t do any more points so 10

3. a) RT

                   b) XZ

                   c) TS

4. a) 26

                  b) 58

                  c) 21.5

                  d) 127

Step-by-step explanation:

2(PT) = AE              2(CP) = AN                 2(CT) = EN

2(13) = AE               2(29) = AN                  2(CT) = 43

  26 = AE                  58  = AN                      CT  = 21.5

Perimeter = AE + AN + EN

                = 26 + 58 + 43

                = 127

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

m∠a is 90°

m∠b is 40°