Curium-243 has a half-life of 28.5 days. in a sample of 5.6 grams of curium-243, how many grams will remain after 12 days? a. 1.08g b.2.8g c.4.18g d.2.09g e.5.6g

The correct answer option is C. 4.18 g.

Step-by-step explanation:

We are given that Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243 and we are to find how many grams will remain after 12 days.

To find the number of remaining grams, we will use the following formula:

where t is the time and h is the half life.

So substituting in the given values to get:

Therefore, 4.18 grams of curium-243 will remain after 12 days.

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it