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1+sina+cosa/sina+cosa-1 - 1+sina-cosa/1-sina+cosa= 2(1+coseca)
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Write the product as a trinomial. (x + 2)(x + 3) x2 + 5x + 6 x2 + 6x + 6 x2 + 6x + 5 x2 + 5
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The reflexive property of congruence lets you say that ∠pqr ≅
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1+sina+cosa/sina+cosa-1 - 1+sina-cosa/1-sina+cosa= 2(1+coseca)...
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