Geometric sequence question, plz answer

a10 = 1024/729                                   a10 =- 1024/729

Step-by-step explanation:

Formula for geometric sequence

an = a r^n

The third term is

24 = a r^3

The fifth terms is

32/3  =a r^5

Divide these equations

32/3 = ar^5

24  = a r^3

32/3

 = r^2

24

Copy dot flip

32/3 * 1/24  = r^2

Divide the top and bottom by 8

4/3*3 = r^2

2*2/(3*3) = r^2

Take the square root of each side

sqrt (2*2/(3*3) =sqrt (r^2)

± 2/3 = r

Now we need to solve for a

an = a (2/3)^n     or                      an = a (-2/3)^n

Using the third term

24 = a (2/3)^3                          24 = a (-2/3)^3  

24 = a (8/27)                              24 = a (-8/27)

Multiply by 27/8                      Multiply by -27/8

24*27/8 = a                             24*-27/8 = a

81=a                                                     -81=a

an = 81 (2/3)^n     or                      an = -81 (-2/3)^n

Now we want to find the 10th term.  Let n =10

a10 = 81 (2/3)^10     or                      a10 = -81 (-2/3)^10

a10 = 1024/729                                   a10 =- 1024/729

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: