It is given that parallelogram jklm is a rectangle and by the definition of a rectangle, ∠jml and ∠klm are right angles. ∠jml≅∠klm because . jm⎯⎯⎯⎯⎯≅kl⎯⎯⎯⎯⎯ because , and ml⎯⎯⎯⎯⎯⎯≅ml⎯⎯⎯⎯⎯⎯ by the reflexive property of congruence. by the , △jml≅△klm . because , jl⎯⎯⎯⎯≅mk⎯⎯⎯⎯⎯⎯ .

Step-by-step explanation:

It is given that the parallelogram JKLM  is a rectangle and by the definition of rectangle, ∠JML and ∠KLM are right angles, ∠JML ≅∠KLM because all right angles are congruent.

\overline{JM}≅\overline{KL} because opposite sides of a parallelogram are congruent, and \overline{ML}≅\overline{ML} by the reflexive property of congruence. By the SAS congruence postulate, ΔJML≅ΔKLM, because corresponding parts of congruent triangles are congruent, \overline{JL}≅\overline{MK}.

{3 + i, 3 - i, 3, -1}

step-by-step explanation:

x = 3 ± √(5+y)