Asoccer ball is kicked into the air from the ground. if the ball reaches a maximum height of 25 ft and spends a total of 2.5 s in the air, which equation models the height of the ball correctly? assume that acceleration due to gravity is –16 ft/s2. h(t) = at2 + vt + h0

its A on ed-genuity

Step-by-step explanation:

Given the equation:        .....[1]

If t = 0,  then h = 0.

Substitute these in [1] we get;

Simplify:

Also, it is given that the acceleration due to gravity (a) =

then;

[1] ⇒

If the ball reaches a maximum height of 25 ft and spends a total of 2.5 s in the air.

⇒ total time = 2.5 s

The height of ball is maximum at t =1.25 s

⇒h(1.25) = 25 ft

we have;

Solve for velocity(v);

Divide both sides by 1.25 we get;

Add 20 both sides to an equation we get;

v = 40 ft\s

Therefore, the equation become to models the height of the ball is;

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

step-by-step explanation:

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