Find the area of a 45°-45°-90° triangle with a hypotenuse of 24. a. 144 square units c. 99 square units b. 125 square units d. 100 square units

Area=1/2 times base times height

remember that 45-45-90 triangle has sides of x,x and x√2
(legs are measure x and hypotonuse=x√2)

the legs are equal and are also the base and height
find the legs (x=leg)

hypotonuse=24
24=x√2
divide both sides by √2
24/(√2)=leg=base=height

volume=1/2 times base times heigth
V=1/2 times (24/√2) times (24/√2)
V=1/2 times (576/2)
V=576/4
V=144 units^2

answer is A