The equation of line ab is y = 5x + 1. write an equation of a line parallel to line ab in slope-intercept form that contains point (4, 5). (1 point) y = 5x − 15 y = −5x + 15 y = 1 over 5 x + 21 over 5 y = 1 over 5 x − 29 over 5

y = 5x -15

Step-by-step explanation:

A parallel line has the same slope, hence the same x-coefficient in its equation. This makes it be ...

... y = 5x +b . . . . . . . for some value of b that will give the desired point

Putting the given point values into the equation, we can find the necessary y-intercept constant.

... 5 = 5·4 +b

... 5 - 20 = b = -15

The the desired equation is ...

... y = 5x -15

step-by-step explanation:

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