What’s the perimeter and area of the triangle above?

Hello from MrBillDoesMath!

Perimeter =  18 cos(42) + 18 sin(42) + 18

Area =  162 * sin(42) cos(42)

Discussion:

x = 18 * cos(42) and y = 18 sin(42)  so...

Perimeter = x + y + 18 =

                    18 cos(42) + 18 sin(42) + 18    which is approx

                    18 (.743) + 18 (.669) + 18  = 43.42

Area =  (1/2) bh = (1/2) yx =

                          = (1/2) ( 18 sin(42)) (18 cos(42))

                          = (1/2) (18*18) sin(42) cos(42)

                          = (324/2) sin(42) cos(42)

                          = 162 * sin(42) cos(42)

which is approx

                          = 80.56

Thank you,

MrB

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