Combine like terms: 2y^2 + 2(4y^2 − 3)

10y^2-6

Step-by-step explanation:

2y^2=2(4y^2-3)

2x4y^2=8y^2

2x(-3)=(-6)

2y^2+8y^2-6

10y^2-6

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you

what? that isnt a question

step-by-step explanation: