What is th product ? y2+3y+7 8y2+y+1

8y⁴+25y³+60y²+10y+7

Step-by-step explanation:

Given two functions

y²+3y+7 and 8y²+y+1

To take the product of both functions means multiplying both functions together.

(y²+3y+7)(8y²+y+1)

Opening up the bracket we have:

= 8y⁴+y³+y²+24y³+3y²+3y+56y²+7y+7

Collecting the like terms

= 8y⁴+y³+24y³+y²+3y²+56y²+3y+7y+7

Adding up the functions with the same degree and simplifying the expression will give;

= 8y⁴+25y³+60y²+10y+7

This gives the product of both functions

i belive those are the ones that are under 90 degreese.

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: