1- the width of a rectangular box is twice the height and depth is 5 feet. if the volume is 160 ft 3, find the dimensions of the box. 2- the perimeter of the rectangle room is 96 feet. if the length is 6 feet more than the width, find the dimensions of the room.

2,600 divided by 80 = 32.5

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2