Suppose i have either a fair coin or a bent coin, and i don't know which. the bent coin has a 60% probability of coming up heads. i throw the coin ten times and it comes up heads 8 times. what is the probability i have the fair coin vs. the probability i have the bent coin?

Last part of Question:

Assume at the outset there is an equal (.5,.5) prior probability of either coin.

0.36

Step-by-step explanation:

Let P(A) = Probability of fair coin = 0.5

Let P(B) = Probability of bent coin = 0.5

The coin was thrown 10 times

The number of possible events, E = 10

P(E | A) =

P(E | A) =0.0440

P(E |B) =

P(E |B) = 0.1209

Probability of having the fair coin vs the probability of having the bent coin = 0.2665/0.7334

i can answer this question sweetie!

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft