Father is four times older than his son. in 14 years the father will be twice as old. what are their current ages?

The son is 7 years old

The father is 28 years old

Step-by-step explanation:

f = fathers age

s = sons age

f = 4s

In 14 years  ( so we add 14 to the age)

f+14 = 2(s+14)

We have 2 equations and 2 unknowns

Replace every f with 4s  (from the first equation)

4s+14 =2(s+14)

Distribute the 2

4s+14 = 2s+28

Subtract 2s from each side

4s-2s+14 = 2s-2s+28

2s+14 = 28

Subtract 14 from each side

2s-14-14 = 28-14

2s = 14

Divide by 2

2s/2 =14/2

s =7

The son is 7 years old

Now lets calculate the fathers age

f =4s

f =4*7

f = 28

The father is 28 years old

the correct answer is semicircle

step-by-step explanation:

the answer is semicircle because the shorter arc joining two points on the circumference of a circle is known as the minor arc, the larger arc is called the major arc, and a semicircle is a half circle, formed by cutting a whole circle along a diameter line.

hope i .

rounding to the nearest thousandth would be 452,000