What is the antiderivative of 1-cos^2(x)

sin2x + x + c

Step-by-step explanation:

using the trigonometric identity

• cos² x = (cos2x + 1) and

∫cos ax = sin ax

hence

∫(1 - (cos2x + 1)dx

= ∫(1 - cos2x - )dx

= ∫( - cos2x)dx

= x - sin2x + c

where c is the constant of integration

f is the midpoint of

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!