450a^2+242c^2+660ac in factored form

450·a^2 + 242·c^2 + 660·a·c

= 2·(225·a^2 + 330·a·c + 121·c^2)

= 2·((15·a)^2 + 2·(15·a)·(11·c) + (11·c)^2)

= 2·(15·a + 11·c)^2

kk.bj.

step-by-step explanation:

.mnm.kn.kj

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)