Point n has coordinates (-1 , 2) point q is symmetric to point n with respect to the line y=x what are the coordinates of of point m (2 , 0) (1 , -2) (2 , -1) (2 , 2)

Q=(2,-1)

Step-by-step explanation:

We are given point as N=(-1,2)

Point Q is symmetric to point N with respect to line y=x

we know that any point symmetric with respect to  line y=x means inverse of that point

For example: If we have to find symmetric about y=x line of point (a,b)

a changes to b

and b changes to a

so, symmetric of (a,b) with respect to y=x line would be (b,a)

We have point N(-1,2)

-1>2

2>-1

so, we get point as

Q=(2,-1)

i'm sure goog can you get that answer

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.