Evaluate \dfrac{e}{4}+2f-3 4e +2f−3 when e=12e=12 and f=\dfrac12f= 21

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5

Step-by-step explanation:

i think this could be a possible answer (1 / 84) -1

good luck! : d