Adiameter of a circle had endpoints p(-10, -2) and q(4,6) a. find the center of the circle b. find the radius. if your answer is not an integer, express it in radical form. c. write an equation for the circle

Center = -3,2

radius      = sqrt(65)

(x+3)^2 + (y-2)^2 = 65

Step-by-step explanation:

We can find the center of the circle by finding the midpoint of the diameter

midpoint = (x1+x2)/2, (y1+y2)/2

              = (-10+4)/2, (-2+6)/2

               = (-6/2), (4/2)

                 = -3, 2

Center = -3,2  = (h,k)

The radius is the distance from the midpoint to one of the points on the diameter.  Using the points (-3,2) and (4,6)

distance = sqrt ( (x2-x1)^2 + (y1-y2)^2)

              = sqrt(( 4--3)^2 + (6 -2)^2)

             = sqrt(( 4+3)^2 + (6 -2)^2)

               = sqrt( 7^2 + 4^2)

               = sqrt(49+16)

radius      = sqrt(65)

The equation of a circle is given by

(x-h)^2 + (y-k) ^2 = r^2

(x--3)^2 + (y-2)^2 = sqrt(65)^2

(x+3)^2 + (y-2)^2 = 65

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.