Take a look at teen 1's initial polynomials for three layers of hills. teen 1 has described what he thinks each modification to the initial polynomial will do. sketch each curve (in a different color, preferably). (you will be asked to find and repair mistakes in the next section.) (6 points: 2 points for each curve) hill 1: my first layer needs three peaks. i chose three points on the x-axis (the three zeros), and then i wrote each as a binomial to create the first polynomial. f(x) = (x – 1)(x – 3)(x – 4) hill 2: my second layer should be a useful transformation of the first. using the first polynomial as the base, i multiplied it by to flip it and make the hills steeper. then, i added 3 to shift it to the right. f(x) =– (x – 1)(x – 3)(x – 4) + 3 hill 3: this hill should be a shallow parabola that will rise up in the foreground of my picture. f(x) = 4(x–)(x – 5)

This question is based on the graph. Therefore, the errors are:

(1) Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).

(2) Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).

(3) Error is that, multiplying by four makes a steeper slope (not a shallow slope).

Given:

Take a look at teen 1's initial polynomials for three layers of hills. Teen 1 has described what he thinks each modification to the initial polynomial will do.

According to the question,

Attachment of each curve, is below.

(1) I chose three points on the x-axis (the three zeros), and then I wrote each as a binomial to create the first polynomial. F(x) = (x – 1)(x – 3)(x – 4).

Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).

(2) Using the first polynomial as the base, I multiplied it by to flip it and make the hills steeper. Then, I added 3 to shift it to the right. F(x) =– (x – 1)(x – 3)(x – 4) + 3.

Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).

(3)This hill should be a shallow parabola that will rise up in the foreground of my picture. F(x) = 4(x–)(x – 5).

Error is that, multiplying by four makes a steeper slope (not a shallow slope).

Therefore, the errors are in each question,

(1) Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).

(2) Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).

(3) Error is that, multiplying by four makes a steeper slope (not a shallow slope).

For more details, prefer this link:

link

See attachment for graphs

1) Error: 3 zeros (x-intercepts) does not make 3 peaks (vertices)

2) Errors: Multiplying it by a negative is a reflection (not a steeper slope). Adding 3 on the outside of the factors is a vertical shift up (not a horizontal shift to the right).

3) Error: Multiplying by 4 makes a steeper slope (not a shallow slope).

costs the what? what is the cost of the pants?

step-by-step explanation:

if it is $10, then the price is 14.

take 40% of the cost, and then add the cost.

40% of 10 = 4

4+10 = 14.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240