Convert -√3-i to polar form. a. 2cis(pi)/6 b. 2cis5(pi)/6 c. 2cis7(pi)/6 d. 2cis11(pi)/6 e. 2cis4(pi)/6

-sqrt(3) -i = 2 cis (7pi/6)

Step-by-step explanation:

-sqrt(3) -i

We can find the radius

r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)

  = sqrt( 3 + 1)

  = sqrt(4)

  = 2

theta = arctan (y/x)

          arctan (-1/-sqrt(3))

         arctan (1/sqrt(3))

theta = pi/6

But this is in the first quadrant, and we need it in the third quadrant

Add pi to move it to the third quadrant

theta = pi/6 + 6pi/6

         =7pi/6

-sqrt(3) -i = 2 cis (7pi/6)

the answer is a

step-by-step explanation:

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step-by-step explanation:

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