Solve the system by substitution 2x+y=10 x-3y=-2 state whether the system had one solution infinite solutions or no solution

System has only one solution. x= 4 and y = 2.

Step-by-step explanation:

We have given two equations :

2x + y = 10    (1)

x - 3y = -2   (2)

From equation (2), we can write:

x - 3y = -2

or x = -2 + 3y  , substitute this in equation (1).

We get,  2x + y = 10

2*(-2 + 3y) + y = 10

-4 + 6y + y = 10

7y = 10 + 4

y = 14/7 = 2

And x = -2 + 3*2 = -2 + 6 = 4

Hence we get x= 4 and y = 2. System has only one solution

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

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