If you were going to use the quadratic formula to solve the following equation and b=15, what number would you use as the value for the variable ‘a’? -15x+22=12x^2

You would use a = 12

Step-by-step explanation:

The b value is the coefficient that is in front of the x term, that does not have an exponent of 2. It's simply the x term (not the x^2 term)

We're told that b = 15 is used, but we see that -15 is in front of the x term. To fix this contradiction, add 15x to both sides so that you move the x term to the right side

-15x+22 = 12x^2

-15x+22+15x = 12x^2+15x

22 = 12x^2+15x

Now subtract 22 from both sides to move that term over as well

22-22 = 12x^2 + 15x - 22

0 = 12x^2 + 15x - 22

12x^2 + 15x - 22 = 0

12x^2 + 15x + (-22) = 0

The last equation is in the form ax^2 + bx + c = 0 with

a = 12, b = 15, c = -22

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

step-by-step explanation: