Robin is standing on the top of a 40-foot flagpole at 1 p. m. at the same time, a 4-foot child on the ground casts a shadow of length 0.8 feet. if robin is 6 feet tall, how much longer is the shadow of the flagpole and robin together than the shadow of the flagpole alone? specify your answer as a decimal to the nearest tenth.

1.2 ft

Step-by-step explanation:

We can use ratio's to solve this problem.  Put the item on top, and the shadow on the bottom

40 ft flagpole       4 ft child

=

x ft shadow            .8 ft shadow

Using cross products

40 * .8 = 4x

32 = 4x

Divide each side by 4

32/4 = 4x/4

8 = x

The flag pole casts an 8 ft shadow

The question asks how much longer is the shadow of the flagpole and Robin than the flagpole?  In other words, how long is Robins shadow

40 ft flagpole       6ft  Robin

=

8 ft shadow            x ft shadow

Using cross products

40 *x = 6*8

40x = 48

Divide by 40

40x/40 = 48/40

x = 1.2

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950