Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. release your mouse button when the item is place. if you change your mind, drag the item to the trashcan. click the trashcan to clear all your answers. find the diagonal of a square whose sides are of the given measure. given = 7√3

  " 7√6 " .

                →   The answer is:  " 7√6 units " .

Step-by-step explanation:

Method 1:

This will be a "45-45-90" triangle;

which means that in:

(two sides for triangle will be the same).

which is consistent with the information give:

(the two side of the triangle are sides of a "square" ,

 and ALL sides of a square have the "square length" ;

and one side with be 90 degrees (a right triangle);

and the other angles will be 45 degrees (which is 1/2 of 90 degrees because the will cut into "1/2" of each of the "two other 90 degree angles" when a diagonal is drawn to form the "hypotenuse".

So, for "45-45-90" triangles, the side lengths, are:  

     "x, x, x√2 " ;  in which "x√2" represents the side length of the "hypotenuse" ;  and the two "x" values represent the equal values for the other 2 (two) side lengths.,

We are asked to find the "diagonal" of the square;  in which:  "x = 7√3" ;

 That is, we are ask to find the hypotenuse:  "x√3"  ;

 Note:  We are given:  " x = 7√3 " ;

So:  " x√3 " =  " 7 *√3 *√2 = 7 *√6 = " 7√6 ".

The answer is:  " 7√6 units " .

Method 2:

Use the Pythagorean theorem (for right triangles):

 "  a² + b² = c² " ;  

      in which: "c" represents the "side length" of the "hypotenuse" ;

                or:  the "diagonal" of the "square" ; for which we shall solve.

                      "a" and "b" represent the other sides of the right triangle.

                     In this case, "a" and "b" are equal;

                            since "a" & "b" are the side lengths of a square.

                    We are given:  a = b = " 7√3 " .

                      We are to find "c" .

"  a² + b² = c²  " ;  

↔   " c²  = a² + b²  " ;

 →  c²  = (7√3)² + (7√3)²  ;

 →  c²  = (7²) * (√3)² + (7²) (*√3)²  ;

 →  c²  = ( 49*3)    +  (49*3) ;

 →  c²  = (147) + (147) ;

 →  c²  = 294 ;

Take the "positive" square root of each side of the equation;

    to solve for "c" ;

 →  ⁺ √(c²) = ⁺ √294 ;

→  c = ⁺ √294

⁺ √294 =  ⁺ √3 ⁺ √98 ;

                         →   √98 = ⁺ √49⁺ √2 ;

⁺ √294  =  7√3√2  =  7√6 .    

  c = 7√6

The answer is:  " 7√6 units " .

The values obtained by using "both" methods/ match!

Hope this helps!

 Best wishes in your academic pursuits

          — and within the community!

at least two

step-by-step explanation: