If a normal distribution has a mean of 132 and a standard deviation of 20 what is the value that has a z score of 1.8?

168 = x

Step-by-step explanation:

mean  = u=132

standard deviation =sigma = 20

z score =z=1.8

The formula is

z = (x-u)/ sigma

Substituting what we know

1.8 = (x-132)/20

Multiply by 20

1.8*20 = (x-132)/20 *20

36 = x-132

Add 132 to each side

36+132 = x-132+132

168 = x

Multiply the standard deviation by the z-score and add that to the mean:

Value = 132 + (20*1.8) = 132 + 36 = 168

The value would be 168.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24