Suppose a normal distribution has a mean of 38 and a standard deviation of 2. what is the probability that a data value is between 36 and 43? round your answer to the nearest 10th of a percent.

83.5 %

Step-by-step explanation:

The mean is 38 and the standard deviation is 2

38 -2 is 36

36 is one standard deviation below the mean.

43 - 38 is 5

5/2 is 2 1/2 times the standard deviation above the mean

-1< z< 2.5

P ( Z<2.5 )−P (Z<−1 )

P ( Z<−1)=1−P ( Z<1 )

P ( Z<2.5 )-1+P ( Z<1 )

Using the standard normal table

0.9938 - 1 +0.8413

0.8351

83.51%

Rounding to the nearest tenth

83.5%

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

because i took test

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation: