Marsha wants to determine the vertex of the quadratic function f(x)=x^2-x+2. what is the function's vertex?

vertex = ( , )

Step-by-step explanation:

given a quadratic in standard form : ax² + bx + c : a ≠ 0

the x- coordinate of the vertex can be found as

= -

f(x) = x² - x + 2 is in standard form

with a = 1, b = - 1 and c = 2

= - =

substitute this value into the function for the y-coordinate

y = ()² - + 2 =

vertex = ( , )

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: