Is k-2 a factor of (k^3-k^2-k-1)\(k-2)

Hello from MrBillDoesMath!

k-2 is not a factor of k^3-k^2-k-1.

Discussion:

I think you are asking if k-2 is a factor of  (k^3-k^2-k-1). If it were, then substituting k = 2 in the polynomial would yield 0.  Let's check:

2^3 - 2^2 - 2 - 1 =                                "k^3-k^2-k-1"

8 - 4- 2- 1 = 1 <> 0.

So k-2 is not a factor of k^3-k^2-k-1.

Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!

No, K-2 is not a factor of (k^3-k^2-k-1)\(k-2).

Step-by-step explanation:

it 2

step-by-step explanation:

8^1/3=2

step-by-step explanation:

most likely the answer is a.

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