The following function is quadratic. f(x)=(x+4)(x-6) what is the value of the positive x-intercept of the graph of the related equation y = (x+4)(x-6)?

6

You replace f(x) or y with 0, and then solve for x

y = (x+4)(x-6)

(x+4)(x-6) = y

(x+4)(x-6) = 0

x+4 = 0 or x-6 = 0 zero product property

x = -4 or x = 6

The x intercepts are -4 and 6. In this case, only 6 is the positive x intercept.

side note: The term "root" is another way to say "x-intercept"

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: