Write the equation of a line that has a slope of -3 and goes through the point (5,7). a) (y – 5) = -3(x – 7) b) (y + 5) = -3(x + 7) c) (y + 7) = -3(x + 5) d) (y – 7) = -3(x – 5)

The equation of the line would be D) y - 7 = -3(x -5)

Step-by-step explanation:

In order to find this, we must first start with the base form of point-slope form.

y - y1 = m(x - x1)

Now we put the slope in for m and the point in for (x1, y1)

y - 7 = -3(x - 5)

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.