What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)? y = -3/2x+7/2 2y = -3x + 7 2x + 3y - 7 = 0

The equation of the line would be y = -3/2x + 7/2

Step-by-step explanation:

In order to find this, we must first use the slope formula with the two point to find the slope.

m(slope) = (y2 - y1)/(x2 - x1)

m = (5 - -1)/(-1 - 3)

m = 6/-4

m = -3/2

Now that we have the slope, we can use that and either point in point-slope form. Then we solve for y.

y - y1 = m(x - x1)

y + 1 = -3/2(x - 3)

y + 1 = -3/2x + 9/2

y = -3/2x + 7/2

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step-by-step explanation: 2