Ab  passes through  a(-3, 0) and  b(-6, 5).  what is the equation of the line that passes through the origin and is parallel to ab? a.  5x  − 3y  = 0b.  -x  + 3y  = 0c.  -5x  − 3y  = 0d.  3x  + 5y  = 0e.  -3x  + 5y  = 0

C.  -5x − 3y = 0

Step-by-step explanation:

A(-3, 0) and B(-6, 5)

First we find the slope of line AB

Slope of the line parallel to AB =  slope of line AB

When the lines are parallel then their slope are equal

So the slope of line parallel to AB =

The line passes through the origin (0,0)

Use equation y-y1= m (x-x1)

m = -5/3 , x1=0 and y1=0

multiply the whole equation by 3

3y = -5x

Subtract 3x from both sides

0=-5x-3y

-5x - 3y =0

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

215.92 dollars is the answer